6x^2-540=6x

Solution for 6x^2-540=6x equation:

6x^2-540=6x

We move all terms to the left:

6x^2-540-(6x)=0

a = 6; b = -6; c = -540;
Δ = b2-4ac
Δ = -62-4·6·(-540)
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12996}=114$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-114}{2*6}=\frac{-108}{12}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+114}{2*6}=\frac{120}{12}
=10
$